Question

9. Find the values of a and B from the equation 2xsquare+7x+3 if a and beta are zeroes of equation
Also, find the value of (a) asquare+beta sqyare (b) acube +beta cube​

Answer 1

here is answer to questions

Answer 2

Explanation:

${2x}^{2} + 7x + 3 = 0 \\ {2x}^{2} + x + 6x + 3 = 0 \\ x(2x + 1) + 3(2x + 3) = 0 \\ (x + 3)(2x + 3) = 0 \\ x = - 3 \\ x = \frac{ - 3}{2}$

Here, -3 and

$\frac{ - 3}{2}$

are the zeroes. So,

$\alpha = - 3 \\ \beta = \frac{ - 3}{2}$

1. ${ \alpha }^{2} + { \beta }^{2} \\ ( - 3)^{2} + { \frac{( - 3)}{(2)} }^{2} \\ 9 + \frac{9}{4} \\ \frac{45}{9}$
2. ${ \alpha }^{3} + { \beta }^{3} \\ { - 9}^{3} + { \frac{ (- 3)}{(2)} }^{3} \\ - 729 + \frac{27}{8} \\ \frac{5859}{8}$