Math, asked by ak7765892, 6 months ago

9. Find the zeroes of a cubic polynomial p(x) = x3 + 6x2 - x - 30 when it is
given that the product of two of its zeroes is - 6.​

Answers

Answered by Harshikesh16726
1

Answer:

Given cubic polynomial is

p(x)=x

3

−6x

2

+3x+10

The zeros of the polynomial p(x) are of the form a, a+b and a+2b

Then,

a+a+b+a+2b=−

1

−6

=>3a+3b=6

=>a+b=2 ----------------(i)

Also, a(a+b)+(a+b)(a+2b)+a(a+2b)=

1

3

=>a

2

+ab+a

2

+2ab+ab+2b

2

+a

2

+2ab=3

=>3a

2

+2b

2

+6ab=3 ----(ii)

and a(a+b)(a+2b)=−

1

−10

=>a

3

+a

2

b+2a

2

b+2ab

2

=10

From (i), b=2−a

Putting this value in (ii), we get

=>3a

2

+2(2−a)

2

+6a(2−a)=3

=>3a

2

+2(4−4a+a

2

)+12a−a

2

=3

=>−a

2

+4a+5=0

=>a

2

−4a−5=0

=>a

2

−5a+a−5=0

=>a(a−5)+(a−5)=0

=>.(a−5)(a+1)=0

=>a=5 or a=−1

=>b=−3 or b=3 respectively

From equation (iii), we get

at a=5, b=−3

=>5

3

+(5)

2

(−3)+2(5)

2

(−3)+2(5)(−3)

2

=−10

=>125−75−150+90=−10

=>−10=−10 which is true.

and at a=−1, b=3, we have

=>(−1)

3

+(−1)

2

3+2(−1)

2

(3)+2(−1)(3)

2

=−10

=>−1+3−6−18=10

=>−22=−10 which is not true.

Thus, a=5, b=−3

Zeros of the polynomial are 5, 5−3, 5−2×3 ie 5,2,−1

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