Question

9. Find the zeroes of the quadratic polynomial 6x2 + 7x + 2 and verify the relationship between the zeroes and the coefficients.​

Answer 1

Answer:

To get zeros for an expression we should equate the expression with "zero"

Step-by-step explanation:

→6X²+7X+2=0.

→Standard form of an equation is aX²+bX+c=0.

→Then we can take a=6,b=7 & c=2.

→Formula for (Roots of an equation) or (Zeros of the expression) is

X=[-b±√(b²-4ac)]/2a

→Apply the formula

X=[-7±√7²-4(6)(2)]/2(6)

→

X=[-7±√49-48]/12

→

X=[-7±1]/12

→

X=(-7-1)/12  & X=(-7+1)/12

→

X=(-8)/12  &  X=(-6)/12

→

X=(-2/3)&(-1/2)

→Zeros of the expression are -2/3 &-1/2

I hope this is understandable.