9. Find two 2 digit numbers such that their product is 840, the product of their
unit's digits is 20 and the product of their ten's digits is 6.
Answers
Answer:
TE TWO DIGIT NUMBER IS 24 AND 35
Step-by-step explanation:
PROCESS IN MY ATACHEMENT
Answer:
The two 2 digit numbers are 24,35
Step-by-step explanation:
Given,
The product of 2 two-digit numbers = 840
Product of their units digits= 20
Product of their ten's digits = 6
Solution:
Let the 2 two digit numbers be 10a+b and 10c+d, where a and c are their tens digits and b and d their unit's digits.
Given that the product of the two numbers = 840
Then we have,
(10a+b)(10c+d) = 840 ----------------(1)
Since product of their units digits= 20
we have, bd = 20, which is possible only when b,d = 4,5
Let us take b = 4 and d = 5 and substitute in equation (1)
(10a+4)(10c+5) = 840 ------------(2)
Since the product of their ten's digit = 6, we have ac = 6---------(3)
(10a+4)(10c+5) = 840
100ac+50a+40c+20 = 840
100 ×6 +50a+40c +20 = 840
50a+40c +600+20 = 840
50a+40c = 840 - 620 = 220
5a+4c = 22 -----------(4)
ac = 6 , The possible values of (a,c) are (1,6),(2,3),(3,2),(6,1)
When a =1, c = 6,
(4) →5+24 = 29 ≠22
When a = 2, b= 3
(4) →10+12 = 22
Hence the value of a = 2 and c = 3
10a+b = 10×2+ 4 = 24
10c+d = 10×3+5 = 35
∴ The two 2 digit numbers are 24,35
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