Question

9. Find two consecutive multiples of 3 whose product is 648.​

Answer 1

Answer:

(24,27) or ( -24, -27)

Step-by-step explanation:

let the multiples be (x-3) , (x) , (x+3)

given,

             (x-3) (x) = 648

              (x²- 3x) = 648

              x² - 3x- 648=0

              x² - 27x + 24x - 648 =0

              x( x-27) + 24( x- 27) =0

              (x-27) (x+24) =0

             if x= 27, the other number would be 24

             if x= -24, then other number would be -27

hope it helps

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Answer 2

Refers to attachment ♡~