Question

9. Five square flower beds each of sides 1 m are dug on a piece of land 5 m long and 4
m wide. What is the area of the remaining part of the land?​

Answer 1

Answer:

Given :-

• Five square flower beds of side 1 m
• Length of land = 5 m
• Width of land = 4 m

To Find :-

Area of remaining part of land

Knowledge required

• Area of square = side² units
• Area of rectangle = Length × Breadth
• Remaining Area = Area of rectangle - Area of square

Solution :-

Area of 5 square flower = 5 × (side²)

Area of 5 square flower = 5 × (1²)

Area of 5 square flower = 5 × 1

Area of 5 square flower = 5 m²

Now,

Area of land = 5 × 4

Area of land = 20 m²

Remaining Area = Area of rectangle - Area of square

Remaining Area = 20 - 5

Remaining Area = 15 m²

Answer 2

Answer:-

The area of the remaining part of the land is 15 m²

Explanation:-

Given:-

• Five square flower beds each of sides 1 m

• Length of piece of the land is 5 m

• Breadth of piece of the land is 4 m

To find:-

What is the area of the remaining part of the land??

Solution:-

Length of the land is 5 m and

Breadth of the land is 4 m

We know that,

⠀

⠀${\underline{\boxed{\sf{Area\:of\:rectangle=Length×Breadth}}}}$

⠀

.°. Area of piece of the land = (5 × 4) m² = 20 m²

⠀

Measure of square flower bed is 1 m

We also know that

⠀

⠀⠀⠀⠀⠀${\underline{\boxed{\sf{Area\:of\:square=(side)^{2}}}}}$

⠀

.°. Area of the flower bed = 1 × 1 m² = 1 m²

.°. Area of 5 flower beds = 5 × 1 m² = 5 m²

Now,

⠀

Area of the remaining part = Area of piece of the land – Area of flower beds

⠀

$\sf{:\implies Area\:of\:the\:remaining\:part=(20-5)\:m^{2}}$

⠀⠀

$\sf{:\implies Area\:of\:the\:remaining\:part=15\:m^{2}}$

⠀

The area of the remaining part of the lland is 15 m²

⠀

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⠀⠀⠀⠀Additional information

⠀⠀

Square:-

1. Area of square = (side)²

2. Perimeter of square = 4 × side

3. Diagonal of square = √2 × side

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Rectangle:-

1. Area of rectangle = Length × Breadth

2. Perimeter of rectangle = 2(Length + Breadth)

3. Diagonal of rectangle=${\sf \sqrt{(length)^{2}+(breadth) ^{2}}}$

$\setlength{\unitlength}{0.8cm}\begin{picture}(10,5)\thicklines\qbezier(1,1)(1,1)(9,1)\end{picture}\setlength{\unitlength}{0.8cm}\begin{picture}(10,5)\thicklines\qbezier(1,1)(1,1)(9,1)\end{picture}$

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