Question

9. For a d electron, the orbital angular momentum is

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Answer 1

hi dear....

the orbital angular momentum (L)=

$\sqrt{l (l + 1} \frac{h}{2\pi} = \sqrt{6} \frac{h}{2\pi} \\ (l = 2 \: for \: d - orbital)$

hope it helps...

Answer 2

Answer:

For a d electron, the orbital angular momentum is

n=3 so $l$=n-1

I.e.,  $l$=3-1

$l$=2

Hope u got ur answer