Question

9. For what value of k does 15, 36, k form a Pythagorean triplet?
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Answer 1

For Pythagorean triplet a,b,c :

${a}^{2} + {b}^{2} = {c}^{2}$

As given

a=15,b=36,c=k

Therefore,

${15}^{2} + {36}^{2} = {k}^{2} \\ 225 + 1296 = {k}^{2} \\ 1521 = {k}^{2} \\ \sqrt{1521} = k \\ 39 = k$

Answer 2

Answer:

a

2

+b

2

=c

2

As given

a=15,b=36,c=k

Therefore,

\begin{gathered} {15}^{2} + {36}^{2} = {k}^{2} \\ 225 + 1296 = {k}^{2} \\ 1521 = {k}^{2} \\ \sqrt{1521} = k \\ 39 = k\end{gathered}

15

2

+36

2

=k

2

225+1296=k

2

1521=k

2

1521

=k

39=k

Step-by-step explanation:

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