Math, asked by shreybaghel107, 1 year ago

9) For what value of k will the following pair of the following
many solutions.
2x+3y=7, (k-1)x+(k+2)y=3k​

Answers

Answered by ButterFliee
0

Answer:

condition for infinite many solution

a1/a2 = b1/b2= c1/c2

2/(k-1) = 3/(k+2) = -7/-3k

2/(k-1) = 3/(k+2)

use cross product

3k -3= 2k + 4

3k -2k = 4+3

k = 7

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