Question

9. Four identical coins each of radius 1.4 cm are
placed on table such that the rim of each
touches that of the other two. Find the area of
the space left between them.
中
(Hint : Required area = Area of square - 4x
area of 1 quadrant.​

Answer 1

Answer:

1.68 sq cm

Step-by-step explanation:  

Area of square obtained

  $= a^{2} \\= 2.8^{2} \\= 7.84 sq cm$

Space left between them

area of square - 4 *(area of one quadrant)

= area of square - area of one circle

$= 7.84 -\pi *1.4^{2} \\= 7.84 - 6.16\\= 1.68 sq cm$

(the figure given below would help to understand better

space left between them is coloured in red)