Question

9. Given below is the frequency distribution table of
salary (in :) of 80 workers in a factory:
Salary 1000 - 2000 - 3000 - 4000 - 5000 -
(in) 2000 3000 4000 5000 6000
Number
of
8
20 24 14
workers
Find the probability that the salary of a worker
selected at random is
(1) less than 4000
(ii) more than or equal to 3000.
(iii) more than or equal to 2000 but less than
5000
(CBSE 2​

Answer 1

Step-by-step explanation:

total workers= 80 workers

a) Total no. of workers= 80

No of workers less than rupees 4000= 14+8=22

22/80 =11/40

b) Total no. of workers=80

No. of workers more Or equal yo ₹3000= 20+24+14=58=

58 = 58/80 = 29/40

c) Total no. of workers= 80

No. of workers more Or equal to ₹2000 but less than ₹5000 =

14+20+24 = 58/80

=29/40

here is your answer...i am not sure...