Question

9. Given : Parallelogram
ABCD in which
diagonals AC and BD L
intersect at M.
Prove : Mis mid-point A
of LN.
step by step​

Answer 1

$answer = >$

Prove : M is mid-point of LN.

Proof : Diagonals of //gm bisect each other.

MD = MB

Also ∠ADB = ∠DBN (Alternate ∠s) &

∠DML = ∠BMN (Vert. opp. ∠s)

ΔDML = ΔBMN

LM = MN

M is mid-point of LN.

Hence proved.