Question

9. Horizontal range of the projectile is 300m when it
thrown at angle of projection 45°. What will be the
height of the projectile when its horizontal displacement
is 100m ? (g = 10m/s2)​

Answer 1

Answer:

hilu ❤️

Explanation:

if α = 0°, then vertical velocity is equal to 0 (Vy = 0), and that's the case of horizontal projectile motion. As sine of 0° is 0, then the second part of the equation disappears, and we obtain : hmax = h - initial height from which we're launching the object is the maximum height in projectile motion.