9.
How many molecules of Co, will be needed to obtain 1.8 g of glucose according to given reaction.
Reaction : 6CO2 + 6H20 - C6H12O6 + 602
[M. wt C6H12O6
= 180gmol-1
(C = 12, H = 1, 0 = 16)
(A) 0.6 x 6.022 x 1023 (B) 6 x 6.022 x 1023
(C) 0.06 x 6.022 x 1023 (D) 60 x 6.022 x 1023
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