Question

9. How many numbers of different digits lying between 4000 and 6000 be
formed from the digits 1, 2, 3, 4, 5, 6?

Answer 1

Step-by-step explanation:

we have digit 2 3 4 5 6 number 4000 to 6000 between lying are formed using these digits without repetition.

the number can have four digits but 4000 to 6000 between can have five digits total number of 4 digits number between 4000 to 6000 equals to

3×Ppower 4 of 3 =3×24=72

total number of 5 digit number is equal to P powers of 5 =5!=120

so total number of required numbers=120+72=192

friends I hope it will help u