Question

9) If 30% of A = 0.25 of B = 1/5th part of C, then
A:B:C=
A) 10 : 12:15
B) 10:13:17
C) 10:12:13
D) 10 : 12:17​

Answer 1

Given :

30% of A = 0.25 of B = 1/5th part of C

To find :

A : B : C

Solution :

Let's start from what is given :

⇒ 30% of A = 0.25 of B = 1/5th part of C

⇒ (30/100) of A = (25/100) of B = (1/5) of C

⇒ 3/10 of A = 1/4 of B = 1/5 of C

⇒ 3A/10 = B/4 = C/5

Now let :

⇒ 3A/10 = B/4 = C/5 = K

So,

⇒ 3A/10 = K

⇒ 3A = 10K

⇒ A = 10K/3

Again,

⇒ B/4 = K

⇒ B = 4K

And lastly,

⇒ C/5 = K

⇒ C = 5K

Now we can say,

⇒ A : B : C = 10K/3 : 4K : 5K

⇒ A : B : C = 10/3 : 4 : 5

Now multiplying each term by 3 :

⇒ A : B : C = 10 : 12 : 15

∴ Required answer , A : B : C = 10 : 12 : 15    (Option A)

Answer 2

Question:-

If 30% of A = 0.25 of B = 1/5th part of C, then  A : B : C =

A) 10 : 12 : 15

B) 10 : 13 : 17

C) 10 : 12 : 13

D) 10 : 12 : 17​

Given:-

• If 30% of A = 0.25 of B = 1/5th part of C.

Solution:-

Here ,

3A/10 = K

3A = 10K

A = 10K/3

Now ,

B/4 = K

B = 4K

Now ,

C/5 = K

C = 5K

Now ,

A : B : C = 10K/3 : 4K : 5K

A : B : C = 10/3 : 4 : 5

Multiply each term by 3 : -

A : B : C = 10 : 12 : 15