Question

9. If 3sec θ = 5, then find the value of cot θ.​

Answer 1

Answer:

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Answer 2

Answer:

I will write theta in A for m ok

3secA= 5

secA = 5/3

We know that sec²A = 1 + tan²A

So,

(5/3)² = 1 + tan²A

tan²A = (25/9) – 1

tan²A = (25–9)/9

tan²A = 16/9

tanA = √(16/9)

tanA = 4/3

We know that cot A = 1/tanA

So, cot A = 1 ÷ 4/3

cot A = 1 × 3/4

cot A = 3/4

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