Question

9. If a = 4 and b = 5, find the value of a' +63 – 3a²b + 3ab2.​

Answer 1

63-3*16*5+3*4*25

=63-240+300

=123

Answer 2

$\large\underline\bold{Given}$

• a = 4

• b = 5

$\large\underline\bold{To~find}$

• The value of $\sf{a^2 + 63 - 3a^2b + 3ab^2}$

$\large\underline\bold{Solution}$

$\implies$ $\sf{(4)^2 + 63 - 3 \times (4)^2 \times 5 + 3 \times (4) \times (5)^2}$

$\implies$ 16 + 63 - 3 × 16 × 5 + 3 × 4 × 25

$\implies$ 16 + 63 - 240 + 300

$\implies$ 139

Answer 》 139

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