Math, asked by Anonymous, 6 months ago

9. If a^4+b^4 = a^2.b^2 find the value
of a^6 +b^6*​

Answers

Answered by TakenName
1

Answer:

0

Step-by-step explanation:

We are given \sf{a^4+b^4 = a^2b^2}.

After transposing sides we get

\sf{a^4-a^2b^2+b^4=0} ...(1)

Solving the Problem

We need to find the value of \sf{a^6+b^6}.

From its structure, we can tell

\sf{(a^2)^3+(b^2)^3}

After applying identity, we get

\sf{(a^2+b^2)(a^4-a^2b^2+b^4)}

which becomes

\sf{(a^2+b^2)\times0=0} ...Because of (1)

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