Question

9. If a
b
=
b
c
prove that (a+b+c) (a-b+c) = ( a ² +b ² +c ² )​

Answer 1

Answer:

( a2-2ab+b2) + (b2-2bc+C2) + (c2-2ca+a2) = 0 => (a-b)2+(b-c)2+(c-a)+(c-a)2 =0