9) if a refrigerator contains 12 cans such that 7 blue cans and 5 red cans. In how many ways can we remove 8 cans so that atleast 1 blue can and 1 red can remains in the refrigerator
Answers
in 455 Ways we can remove 8 cans so that atleast 1 blue can and 1 red can remains in the refrigerator. if a refrigerator contains 12 cans such that 7 blue cans and 5 red cans
Step-by-step explanation:
a refrigerator contains 12 cans such that 7 blue cans and 5 red cans
atleast 1 blue can and 1 red can remains in the refrigerator
=> we can remove Maximum 6 blue cans & 4 Red Cans
We need to remove 8 cans
So
Red Blue Number of Way
4 4 ⁵C₄ * ⁷C₄ = 5 * 35 = 175
3 5 ⁵C₃ * ⁷C₅ = 10 * 21 = 210
2 6 ⁵C₂ * ⁷C₆ = 10 * 7 = 70
Total number of Ways = 175 +210 +70 = 455
in 455 Ways we can remove 8 cans so that atleast 1 blue can and 1 red can remains in the refrigerator
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