Question

9.
If A = {x:x= 3n+1, ne W, x <10), then final the power set of A​

Answer 1

Answer:

the No. of power set = 1024

Step-by-step explanation:

A = {1, 4, 7, 10, 13, 16, 19, 22, 25, 28}

$3n + 1 = 3(0) + 1 = 1 \\ 3(1) + 1 = 4 \\ 3(2) + 1 = 7 \\ 3(3) + 1 = 10 \\ 3(4) + 1 = 13 \\ 3(5) + 1 = 16 \\ 3(6) + 1 = 19 \\ 3(7) + 1 = 22 \\ 3(8) + 1 = 25$

$3(9) + 1 = 28$

here power set =

${2}^{n}$

n = cardinality of the set. there are 19 elements in the set.

here n(A) = 10

hence

${2}^{10} = 1024$