Question

9.
If f(x)=(x - 1)(x + 2)2 then answer the
following:
Find the value of x at f(x) will have local
maximum
(a)-2 (b) 0 (c)-1 (d) 2​

Answer 1

$\textsf{(x - 1)(x + 2)2 = 0}$

$\bigstar{\textsf{Let's check all the options}}$

$\textbf{Firstly, option (a)}$

$\texttt{(-2-1)(-2+2) = 0}$

=> $\texttt{(-3)(0) = 0}$

=> $\texttt{\large{0 = 0}}$

Option (A) is satisfied, hence it is the answer.

Answer 2

Answer:

the answer is option (A)

Step-by-step explanation:

Let x be -2......

therefore, f(x)=(x-1)(x+2)2

0= (-2-1) . (-2+2)

0= (-3) . (0)

0=0

hence proved....