Question

9. If n(A) = 20, n(B) = 16 and n(AUB) = 30, find n(A intersection B)

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Answer 1

Answer:

n(AnB) =n(A) +n(B) -n(AuB)

= 20+ 16-30

= 36-30

n(AnB) =6

Answer 2

Answer:

=6

Step by Step Explanation:

Given that, n(A)=20

n(B)=16

n(AUB)=30

n(AnB)=?

we know that, n(AUB)= n(A)+n(B)-n(AnB)

n(AnB)= n(A)+n(B)-n(AUB)

=20+16-30

=6

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