9.
If p, q, r are in A.P the p²(q+r), q²'(r +p),r²(p+q) are in
1) A.P.
2) G.P.
3) H.P.
4) A.G.P
Answers
Answered by
0
Answer:
Since the given terms are in AP, the common difference will be same.
=>Second Term−First Term =Third Term −SecondTerm
=>
r+p
1
−
q+r
1
=
p+q
1
−
r+p
1
=>
(r+p)(q+r)
q+r−r−p
=
(p+q)(r+p)
r+p−p−q
=>
(q+r)
q−p
=
(p+q)
r−q
=>(q−p)(p+q)=(q+r)(r−q)
=>q
2
−p
2
=r
2
−q
2
Hence, we can see that p
2
,q
2
,r
2
are in AP.
Answered by
0
I don't know the correct but I think it is GP
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