Question

9)If Seg AB=Seg CD and Seg
CD=Seg EF then Seg AB=?​

Answer 1

Given: AM\times MD=CD \times MB$$

CM

AM

=

MD

MB

To prove: ∠CAB=∠DBA

In △AMC and △BMD

MC

AM

=

MD

BM

& ∠AMC=∠BMD

△AMC∼△MBD [by SAS similarity ]

By corresponding parts of similar triangle;s.

∠CAM=∠DBM

⇒∠CAB=∠DBA

Hence prove