Question

9. If sin A
5
13
then the value of sec A is :​

Answer 1

Answer:

Sin A=5/13

By trigonometric identity,

Sin*2A+Cos*2A=1

: .Cos*2A=1-(5/13)*2

=1-25/169

=169-25

--------

25

=144/25

: .CosA. =12/5

SecA=1/cosA

: .SecA=5/12