Question

9.
If sin theta is equals to minus 5 by 13 and theta not in Q3 then find the value of

tan(90° +0) -- sin(180° – 0)
———————————-——-——
sin(270° - 0) + cos ec(360° – 0)​

Answer 1

Answer:

don't know.................

.....

Answer 2

Answer:

sinθ=−31=>sin2θ=91sin2θ+cos2θ=191+cos2θ=1cos2θ=1−91=98cosθ=±98=±322=>cosθ=322orcosθ=−322

Now sinθ is negative, θ must lie in 3rd or 4th quadrant.

But it is given that θ does not lie in 3rd quadrant..

So θ lies in 4th quadrant

In 4th quadrant cosθ is positive.

=>cosθ=−322