9. If sine = a/b, then find the value of sece + tane
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Answer:
mrk me as brainliest nd thanks me plss
Step-by-step explanation:
The answer is given below :
sinθ = a/b
So, secθ = b/√(b² - a²)
and
tanθ = a/√(b² - a²)
Now,
secθ + tanθ
= b/√(b² - a²) + a/√(b² - a²)
= (b + a)/√(b² - a²)
Thank you for your question.
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