9. if (sqareroot 3-1)/( sqareroot 3+ 1) = a - b sqareroot 3, then the values
of a and bare
1 and 2
3 and 2
4 and 3
2 and 1
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Answer:
Explanation:
(i) a+b3–√=3–√+13–√−1=3–√+13–√−1×3–√+13–√+1
=3+1+23–√(3–√)2−(1)2=4+23–√3−1=2(2+3–√)2=2+13–√
Comparing, we get
a=2, b=1
(ii) a+b3–√=5+23–√5−23–√=5+23–√5−23–√×5+23–√5+23–√
=(5)2+(23–√)+2(5)(23–√)(5)2−(23–√2)=25+12+203–√25−12
=37+203–√13=3713+203–√13
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