Question

9. If the area of a rhombus is 96 cm and one of its diagonals is 16 cm, find its perimeter
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Answer 1

Answer:

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Answer 2

Answer:

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Step-by-step explanation:

Area=96 cm sq.

Diagonal=16cm

Since a rhombus has equal diagonals so the length of diagonal is 8 cm.

Area of rhombus= 1/2* d1 *d2

96 = 1/2 * 16*d2

d2 = 12 cm

Length of diagonal 2 is 12 cm.

Half of this diagonal is 6 cm.

Now pythagoras th.

h2 = p2 + b2

h2 = (6)2 + (8)2

h2 = 36 + 64

h2 = 100

h = √100

h = 10 cm

So we got one side.

The sides of rhombus are all equal.

Perimeter of rhombus = 4*Side

= 4 * 10

= 40 cm

Perimeter is 40 cm.