Question

9 - If the distance between the points (4, p) and (1, 0) is 5, then the value of p is​

Answer 1

d = 5

(4 , p) = (x1 , y1)

(1 , 0) = (x2 , y2)

$d = \sqrt{( {x2 - x1)}^{2} + {(y2 - y1)}^{2} } \\ \\ 5 = \sqrt{ {(1 - 4)}^{2} + {(0 - p)}^{2} } \\ \\ 5 = \sqrt{ {( - 3)}^{2} + {0}^{2} + {p}^{2} - 2 \times 0 \times \: p } \\ \\ 5 = \sqrt{9 + {p}^{2} } \\ \\ 5 = 3 + p \\ p = 5 - 3 \\ p = 2$

Answer 2

Answer :- P=4.

Refer to the photo given.