Math, asked by EZEQUEL21, 5 months ago

9. If the jeepney fair is P6.50 in the first 4 kilometers and P1.50 in every succeeding
kilometer, how much is the fair of a 10.5 - kilometer trip?

Answers

Answered by ashleygayonsmith
1

Answer:

409.5

Step-by-step explanation:

6.50 × 4 × 1.50 × 10.5 = 819/

2

= 409 1/

2

= 409.5

Answered by amitnrw
0

Given : jeepney fair is P6.50 in the first 4 kilometers  

P1.50 in every succeeding kilometer  

To Find :  fair of a 10.5 - kilometer trip

Solution:

C represent fair

d represent  distance

C  = 6.50     if   0 < d ≤ 4

C  = 6.50 + 1.50(d - 4)    if 4 < d

= 6.50 + 1.50(d - 4)  

= 6.50 + 1.5d - 6

= 1.5d + 0.5

Hence piecewise function is :

C=\left \{ {{6.5 \quad \quad 0&lt;d\leq4} \atop {1.5d+0.5}\quad 4 &lt; d} \right.

fair of a 10.5 - kilometer trip

10.5 >  4

Hence C = 1.5d + 0.5

C = 1.5(10.5) + 0.5

=> C = 16.25  

Hence Fair is P 16.25

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