Question

9. If the variance of 1,2,3,4,
............,10 is 99/12, then S.D. of
3,6,9,12,...........,30 is *​

Answer 1

Answer:

here is your answer...

Step-by-step explanation:

Given, σ210=9912=334σ102=9912=334

=> σ10=33−−√2σ10=332

SD of required series = 3σ10=333−−√23σ10=3332

hope it helps you...

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