Question

9. If x = 1 - V2 , find the value of х х​

Answer 1

Answer:

3-2√2

Step-by-step explanation:

x =1-√2

then

xx=(1-√2)(1-√2)

${x}^{2} = {(1 - \sqrt{2} )}^{2}$

${x}^{2} = {1}^{2} - 2 \times 1 \times \sqrt{2} + \sqrt{ {2}^{2} } (formula\: applied=(a-b)^2=a^2-2ab+b^2\\ {x}^{2} = 1 - 2 \sqrt{2} + 2 \\ {x}^{2} = 3 - 2 \sqrt{2}$

so your answer is 3-2√2

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