Math, asked by mahekpanchal87, 3 months ago


9. If x= 3 is a solution of the quadratic equation 3x2 + 2kx + 3 = 0, find the value of k.​

Answers

Answered by shalinithore100
1

Step-by-step explanation:

Since x=

2

−1

is a root of the given equation. So, it satisfies the equation

i.e., 3(−

2

1

)

2

+2k(−

2

1

)−3=0⇒

4

3

−k−3=0

⇒k=−

4

9

Answered by adityaverma674
2

Put the value of x=3 in 3x² + 2kx +3 = 0

==> 3(3)² + 2k(3) + 3 = 0

==> 27 + 6k + 3 = 0

==> 30 + 6k = 0

==> 6k = -30

==> k = -30/6

==> k = -5

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