Math, asked by X78, 11 months ago

9. If x = 6a + 8 + 9c; y = 2b - 3a - 6c and
Z= C-b+ 3a; find :
(1) x+y+z
(ii) x - y + z
(iii) 2x-y-3z (iv) 3y – 22 – 5x​

Answers

Answered by TakenName
5

Answer:

All four answers are below!

Step-by-step explanation:

x = 6a + 9c + 8

y = - 3a + 2b - 6c

z = 3a - b + c

(1) x + y + z

( 6 - 3 + 3 )*a + ( 0 + 2 -1 )*b + ( 9 - 6 + 1 )*c + 8

= 6a + b + 4c + 8

(2) x - y + z

( 6 + 3 + 3 )*a + ( 0 - 2 - 1 )*b + ( 9 + 6 + 1 )*c + 8

= 12a - 3b + 16c + 8

(3) 2x - y - 3z

( 12 + 3 - 9 )* a + ( 0 - 2 + 3 )*b + ( 18 + 6 - 3 )*c + 16

= 6a + b + 21c + 16

(4) - 5x +3y - 22

( -30 - 9 )*a + 6b+ ( - 45 - 18 )*c - 40 - 22

= - 39a + 6b- 63c - 62

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