Math, asked by ayeshazabreen204, 1 day ago

9. If x, Br. are zubes of folynomial 423-28 ²47, x match the follaing a) + B+x a b) * B+Br + roc ( ) ) / c) apr c ) C) is - 4 2 6 (نور)​

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Answered by sunitadevi62288
0

9. If x, Br. are zubes of folynomial 423-28 ²47, x match the follaing a) + B+x a b) * B+Br + roc ( ) ) / c) apr c ) C) is - 4 2 6 (نور)

Answered by sudiproul112
1

Answer:

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If a>b>0 and a

3

+b

3

+27ab=729 then the quadratic equation ax

2

+bx−9=0 has roots α,β(α<β). Find the value of 4β−aα.

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a>b>0

Simplify the given equation.

a

3

+b

3

+27ab=729

⇒a

3

+b

3

+(−9)

3

−3ab(−9)=0

Using:- a

3

+b

3

+c

3

−3abc=(a+b+c)(a

2

+b

2

+c

2

−ab−bc−ca)

⇒(a+b−9)(a

2

+b

2

−ab+9a+9b+81)=0

therefore

a+b−9=0

a+b=9

Let, f(x)=ax

2

+bx+c

ax

2

+bx−9=0 →α+β=

a

−b

⇒αβ=

a

−9

(α<β)

a>b>0

f(1)=a+b−9

Thus it is clear that 1 is the root of given quadratic equation.

either α=1 or β=1

if β=1

α=

a

−9

We need

4β−aα=4×1−a(−

a

9

)

=4+9

=13.

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