Question

9. If x+y=9 and xy = 16, find the value of (x² + y2).
Multinle Choice Questions (MCQs)​

Answer 1

Answer:

49

Step-by-step explanation:

(X+Y) = 9

Squaring both sides we get.

$(x+y)^{2} = 9^{2}$

$x^{2} +y^{2} + 2xy = 81$

Putting value of xy from question.

We get

$x^{2} +y^{2} +2(16) = 81$

$x^{2} +y^{2} + 32 = 81\\\\x^{2} +y^{2} = 81-32\\\\x^{2} +y^{2} = 49$

HOPE IT HELPS YOU

Answer 2

Answer:

49

Step-by-step explanation:

(x+y)^2 - 2xy

= 9^2 - 2*16

= 81 - 32

= 49