9. If x3 - hx2 + kx - 9 has a factor of x2 + 3, then the values of h and k are
(1) h = 3, k = 3
(2) h = 2, k = 2
(3) h = 2, k = 1
(4) None of these
Answers
Step-by-step explanation:
Step-by-step explanation:x^3-h.x^2+k.x-9
Step-by-step explanation:x^3-h.x^2+k.x-9=x.(x^2+3)-h.x^2-3.x+k.x-9
Step-by-step explanation:x^3-h.x^2+k.x-9=x.(x^2+3)-h.x^2-3.x+k.x-9=x.(x^2+3)-h.(x^2+3)+3.h-3.x+k.x-9.
Step-by-step explanation:x^3-h.x^2+k.x-9=x.(x^2+3)-h.x^2-3.x+k.x-9=x.(x^2+3)-h.(x^2+3)+3.h-3.x+k.x-9.=x.(x^2+3)-h.(x^2+3)+x.(k-3)+(3.h-9).
Step-by-step explanation:x^3-h.x^2+k.x-9=x.(x^2+3)-h.x^2-3.x+k.x-9=x.(x^2+3)-h.(x^2+3)+3.h-3.x+k.x-9.=x.(x^2+3)-h.(x^2+3)+x.(k-3)+(3.h-9).=(x^2+3).(x-h) + x.(k-3)+3.(h-3).
Step-by-step explanation:x^3-h.x^2+k.x-9=x.(x^2+3)-h.x^2-3.x+k.x-9=x.(x^2+3)-h.(x^2+3)+3.h-3.x+k.x-9.=x.(x^2+3)-h.(x^2+3)+x.(k-3)+(3.h-9).=(x^2+3).(x-h) + x.(k-3)+3.(h-3).x^3-h.x^2+k.x-9 = (x^2+3).(x-h) +{x.(k-3)+3.(h-3)}.
Step-by-step explanation:x^3-h.x^2+k.x-9=x.(x^2+3)-h.x^2-3.x+k.x-9=x.(x^2+3)-h.(x^2+3)+3.h-3.x+k.x-9.=x.(x^2+3)-h.(x^2+3)+x.(k-3)+(3.h-9).=(x^2+3).(x-h) + x.(k-3)+3.(h-3).x^3-h.x^2+k.x-9 = (x^2+3).(x-h) +{x.(k-3)+3.(h-3)}.Dividend. = divisor. quotient + remainder.
Step-by-step explanation:x^3-h.x^2+k.x-9=x.(x^2+3)-h.x^2-3.x+k.x-9=x.(x^2+3)-h.(x^2+3)+3.h-3.x+k.x-9.=x.(x^2+3)-h.(x^2+3)+x.(k-3)+(3.h-9).=(x^2+3).(x-h) + x.(k-3)+3.(h-3).x^3-h.x^2+k.x-9 = (x^2+3).(x-h) +{x.(k-3)+3.(h-3)}.Dividend. = divisor. quotient + remainder.Here (x^2+3) is a factor of x^3-h.x^2+kx-9 so that remainder is zero.
Step-by-step explanation:x^3-h.x^2+k.x-9=x.(x^2+3)-h.x^2-3.x+k.x-9=x.(x^2+3)-h.(x^2+3)+3.h-3.x+k.x-9.=x.(x^2+3)-h.(x^2+3)+x.(k-3)+(3.h-9).=(x^2+3).(x-h) + x.(k-3)+3.(h-3).x^3-h.x^2+k.x-9 = (x^2+3).(x-h) +{x.(k-3)+3.(h-3)}.Dividend. = divisor. quotient + remainder.Here (x^2+3) is a factor of x^3-h.x^2+kx-9 so that remainder is zero.x.(k-3)+3.(h-3)=0. therefore
Step-by-step explanation:x^3-h.x^2+k.x-9=x.(x^2+3)-h.x^2-3.x+k.x-9=x.(x^2+3)-h.(x^2+3)+3.h-3.x+k.x-9.=x.(x^2+3)-h.(x^2+3)+x.(k-3)+(3.h-9).=(x^2+3).(x-h) + x.(k-3)+3.(h-3).x^3-h.x^2+k.x-9 = (x^2+3).(x-h) +{x.(k-3)+3.(h-3)}.Dividend. = divisor. quotient + remainder.Here (x^2+3) is a factor of x^3-h.x^2+kx-9 so that remainder is zero.x.(k-3)+3.(h-3)=0. thereforek-3=0 => k= 3.
Step-by-step explanation:x^3-h.x^2+k.x-9=x.(x^2+3)-h.x^2-3.x+k.x-9=x.(x^2+3)-h.(x^2+3)+3.h-3.x+k.x-9.=x.(x^2+3)-h.(x^2+3)+x.(k-3)+(3.h-9).=(x^2+3).(x-h) + x.(k-3)+3.(h-3).x^3-h.x^2+k.x-9 = (x^2+3).(x-h) +{x.(k-3)+3.(h-3)}.Dividend. = divisor. quotient + remainder.Here (x^2+3) is a factor of x^3-h.x^2+kx-9 so that remainder is zero.x.(k-3)+3.(h-3)=0. thereforek-3=0 => k= 3.h-3=0=> h=3.
Step-by-step explanation:x^3-h.x^2+k.x-9=x.(x^2+3)-h.x^2-3.x+k.x-9=x.(x^2+3)-h.(x^2+3)+3.h-3.x+k.x-9.=x.(x^2+3)-h.(x^2+3)+x.(k-3)+(3.h-9).=(x^2+3).(x-h) + x.(k-3)+3.(h-3).x^3-h.x^2+k.x-9 = (x^2+3).(x-h) +{x.(k-3)+3.(h-3)}.Dividend. = divisor. quotient + remainder.Here (x^2+3) is a factor of x^3-h.x^2+kx-9 so that remainder is zero.x.(k-3)+3.(h-3)=0. thereforek-3=0 => k= 3.h-3=0=> h=3.h=3 , k= 3. Answer
please