Question

9. In a 3-digit number, unit's digit, ten's digit and hundred's digit are in the ratio
1:2:3. If the difference of original number and the number obtained by reversing the
digits is 594, find the number​

Answer 1

Answer:

Let x be the ratio

Then, the no is 100x+20x+3x and the reverse is 300x+20x+1x By question,we have,

(100x+20x+3x)-(300x+20x+1x)=594

=>123x-321x=594

=>-198x=594

=>x=594/-198

=>x= -3

Hence, the no. is -369.

Answer 2

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Given:

Ratio in the digits of a three digit number = 1:2:3

Let us consider unit digit be ‘x’

Tens digit be ‘2x’

and hundreds digit be ‘3x’

So the number is x+10×2x+100×3x

=x+20x+300x

=321x

By reversing the digits,

Unit digit be ‘3x’

Ten’s digit be ‘2x’

Hundreds digit be ‘x’

So the number is 3x+10×2x+100×x

=3x+20x+100x

=123x

According to the condition,

321x–123x=594

198x=594

x=594/198

 =3

∴The number is = 321x

=321×3=963