Question

(9) In a 6 digit number, the digit in ones place is more than the digit in
ten thousands place by 7, the digit in hundreds place is less
than the digit in thousands place by 2, the digit in tens place is
more than the digit in hundred thousands place by 4, the digit in
hundred thousands place is less than the digit in hundreds
place by 3, the digit in thousands place is less than the digit in
ones place by 1. If the number at ones place is 8, find the
number.​

Answer 1

Answer:

∴ The number will be 364281.

Step-by-step explanation:

Given:

In the question, the number is the six-digit number.

The digit of thousands place is 4.

Calculation:

Given that, the digit of thousands place is 4.

Since digit at ten's place is double that of the digit at thousand's place.

⇒ The digit at ten's place = 2 × 4 = 8

The digit at hundred's place is half of the digit at thousand’s place.

⇒ The digit at hundred's place = 4/2 = 2

The digit at the unit's place is half of the digit at the hundred's place.

⇒ The digit at the unit's place = 2/2 = 1

The digit at Ten thousand's place is the sum of the digits at thousands

and hundred's place.

⇒ The digit at Ten thousand's place = 4 + 2 = 6

The digit at lakh's place is half the digit at ten thousand's place.

⇒ The digit at lakh's place = 6/2 = 3

If we arrange the number, the number will be = 364281