9. In a cricket match. Karan faces 50 balls. He hits 10 fours, 5 sixes and remaining
singles in his score of 82 runs. Find the probability that on playing next ball he
will:
(i) hit a four
(ii) make a single run.
(iii) not be able to score.
Answers
Answer:
23/50
Step-by-step explanation:
Total number of balls faced = 50
Total number of possible outcomes = 50
It is given that he hits 10 boundaries and 5 sixes.
Number of balls in which he score boundaries = 10
Number of balls in which he scores six = 5
Total runs in boundaries and sixes = 10×4+5×6
= 40+30
= 70
Total runs scored = 82So,
runs scored in singles
= 82 − 70
= 12
Number of balls faced for singles = 12(1).
Number of balls in which he score boundaries = 10
Number of favourable outcomes = 10
P(hitting 4) = Number of favourable outcomes
Total number of possible outcomes = 1050 = 15(2).
Number of balls in which he scores sixes=5
Number of favourable outcomes = 5
P(hitting 6) = Number of favourable outcomes
Total number of possible outcomes = 550 = 110(3).
Number of balls in which he does not score run
= 50 − (10+5+12)
= 50 − 27
= 23
Number of favourable outcomes
= 23P(no run)
= Number of favourable outcomes.
Total number of possible outcomes = 23/50