Math, asked by seemap9108, 1 year ago

9. in a group of 12 boys if two boys aged 14 and 18 are replaced by two other boys the average age drops by 1 year. what is the average age of the two new boys?

Answers

Answered by ShubhamSadhukhan
0

Answer:

10 years

Step-by-step explanation:

The average age of 12 boys decreased by 1 year, this means the total(sum) age of the boys decreased by (12x1) = 12 years.

==> So, the sum of ages of the two new boys = (14+18-12) = 20 years.

==>So. the average age of the two new boys = (20/2) = 10.

Answered by Agastya0606
0

Given,

Total number of boys = 12

Age of two boys = 14 and 18

To Find,

The average age of two new boys due to which the average dropped by 1.

Solution,

The formula for calculating the average is

Average = sum of observation/number of observation

Let S' be the sum of age of the remaining 10 boys and the average be x

In first case

(12+14+S')/12 = x

Now, these two boys are relaced

(S'+b₁+b₂)/12 = x-1

(S'+b₁+b₂)/12+1 = x

Equating both the values of x

(12+14+S')+/12 = (S'+b₁+b₂)/12+12/12

26+S' = S'+b₁+b₂+12

b₁+b₂ = 14

(b₁+b₂)/2 = 14/2 = 7

Hence, the average age of the two new boys is 7.

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