9 in a horse racing competition there were 18 horses numbered 1 to 18. the organizers assigned a probability of winning the race to each horse, based on the horses' health. the probability that horse 1 would win is (1/7), that 2 win is 1/8 and that 3 would win is 1/7. assuming that tie is not possible, find chance that one of 3 will win the race.
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total probability 1/1
probability of 3 horses winning 1/7+1/8+1/7= 8/56+7/56+8/56=23/56
probability of them winning= 23/56
hope it helps
probability of 3 horses winning 1/7+1/8+1/7= 8/56+7/56+8/56=23/56
probability of them winning= 23/56
hope it helps
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