Math, asked by shan3005, 10 months ago

9) In a parallelogram ABCD find the measure of the all the angles if one of its angles is 15˚less than twice the smallest angle​

Answers

Answered by Sudhir2580
1

Answer:

Step-by-step explanation:

First we know that a parallelogram has four angles and the sum of its two adjacent angles is 180° and according to the question

Let the smallest angle be x

And then the other angle 2x -15

So according to the angle sum property of parallelogram

X + 2X -15° = 180°

3X = 195°

X = 65°

So now, the smallest angle of the parallelogram is 65° and the other angle 115° .

So now, all the angles of the parallelogram are as follows :

65° , 115°, 65°, 115° .

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