Question

9. In a PQR, Q = 90°. If PQ = 10 cm and PR = 15 cm.
Then find the value of tan²P + sec² P + 1​

Answer 1

Step-by-step explanation:

First find PR using pythogoras

PR=√( 15^2 - 10^2 )= 5√5

Now find ratios

tan P = 5√5/10 = √5 / 2

sec P = 10 / 15 = 2 / 3

So required value

${( \frac{ \sqrt{5} }{2} })^{2} + {( \frac{2}{3}) }^{2} + 1 \\ = \frac{5}{4} + \frac{4}{9} + 1 \\ = \frac{45 + 16 + 36}{36} \\ = \frac{97}{36}$

Answer 2

Step-by-step explanation:

the answer is 97/36 .

thank you all friends