Question

9. In A PQR, ZQ = 90°. Equilateral triangles
APQ. BQR and CPR are drawn on the
sides PQ, QR and PR respectively. Prove
that APQ + BQR = CPR.
APQ BOR
(Hint: Find the value of
in terms
+
CPR CPR
of the squares of the sides of A PQR
and use Pythagoras theorem.]​

Answer 1

Answer:

Angle Q = 90 in triangle PQR. The equilateral triangles APQ, BQR, and CPR are drawn on the sides PQ, QR, and PR, respectively. Prove that APQ + BQR = CPR