9.In a set of four integers, the average of the two smallest integers is 102, the average of the three smallest integers is 103, the average of all four is 104. Which is the greatest of these integers?
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Answered by
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Answer:
107 is the answer
Step-by-step explanation:
Let the integers be a,b,c,d
such that a<b<c<d
2
a+b
=102⇒a+b=204
3
a+b+c
=103⇒a+b+c=309
4
a+b+c+d
=104⇒a+b+c+d=416
⇒d=416−309=107
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