Question

9. In a triangle ABC, angle A = 2 angle B and AngleA= 1/3 angle C, find the measures all three angles.

Answer 1

Answer:

Let /_ A = 2 /_ B = 1/3 /_ C = k

= /_A = k

= /_ B = k/2 = 0.5 K

= /_ C = 3k

= /_A + /_ B + /_ C = 180 (Since sum of all angles in a triangle is 180 degrees)

= k + 0.5k + 3k = 180

4.5 k = 180

k = 180 / 4.5

k = 40 degrees

= /_A = k = 40 degrees

= /_ B = k/2 = 0.5 K = 0.5 × 40 = 20 degrees

= /_ C = 3k = 3 × 40 = 120 degrees

Answer 2

Answer:

The above picture is the answer. Hope you will understand..